Top Posters
Since Sunday
New Topic  
Gman01234 Gman01234
wrote...
Posts: 101
Rep: 0 0
3 years ago
Pure acetic acid (CH3COOH) is a liquid and is known as glacial acetic acid. Calculate the molarity of a solution prepared by dissolving 10.00 mL of glacial acetic acid at 25 °C in sufficient water to give 500.0 mL of solution. The density of glacial acetic acid at 25 °C is 1.05 g mL-1.

▸ 1.26 × 103  mol L-1

▸ 21.0 mol L-1

▸ 0.0210 mol L-1

▸ 0.350 mol L-1

▸ 3.50 × 10-4  mol L-1
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
Read 103 times
1 Reply
Replies
Answer verified by a subject expert
jodie1jodie1
wrote...
Posts: 64
Rep: 0 0
3 years ago
Sign in or Sign up in seconds to unlock everything for free
More solutions for this book are available here
1

Related Topics

Gman01234 Author
wrote...

3 years ago
Thank you, thank you, thank you!
wrote...

Yesterday
Thanks for your help!!
wrote...

2 hours ago
Brilliant
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  837 People Browsing
Related Images
  
 1444
  
 1503
  
 908
Your Opinion
How often do you eat-out per week?
Votes: 81