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mombefor78 mombefor78
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7 months ago

It can be shown that the change in entropy in heating or cooling a sample is given by the relation ΔS = mc ln (TF/Ti), where m is the mass of the sample, c is the specific heat of the sample, and TF and Ti are the final and initial temperatures, respectively. What is the change in entropy when 20.0 grams of aluminum with a specific heat of 0.900 J/g K is cooled from 60.0°C to 10.0°C?



+2.93 J/K



+2.50 J/K



0.00 J/K



−2.93 J/K

Textbook 
College Physics

College Physics


Edition: 5th
Author:
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localbabe10localbabe10
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7 months ago
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this is exactly what I needed
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This helped my grade so much Perfect
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I appreciate what you did here, answered it right Smiling Face with Open Mouth
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