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ChucklesIris ChucklesIris
wrote...
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9 years ago
Any help would be great- I'm really unclear on how to do this after watching several tutorials and reading the book material.
1. Normal allele 5' CTATGGTGCACCTGACTCCTGAGGAGAAG T 3'
   normal mRNA:
   normal amino acids:
2. Mutant allele 5'CTATGGTACACCTGACTCCTGTGGAGAAG T 3'
   mutant mRNA:
   mutant amino acids:
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wrote...
9 years ago
We know that DNA is double stranded. The first thing you want to ask is: "which strand is the 'allele' referring to? The template or non-template". In this case, it's the non-template based on the 5'-3' direction.

(Look at some photos of DNA--> mRNA on google. That will show the directions that correspond to which strand).

The template strand is complementary and anti-parallel to the mRNA strand. The non-template (coding) strand, which is what you're looking at, is basically the same direction and order as the mRNA with the exception of Uracil instead of Thymine.

Knowing that, you can figure out the mRNA:

DNA: 5' CTA TGG TGC ACC TGA CTC CTG AGG AGA AGT 3'
mRNA:5' CUA UGG UGC ACC UGA CUC CUG AGG AGA AGU 3'

And now, the amino acids you can find by looking at a codon chart (google). Each trinucleotide cluster represents one amino acid. CUA corresponds to leu (leucine).

This is in the N--> C direction:

N-leu-trp-cys-thr-STOP-C

Okay, this would mean that the protein chain would be stopped at that point and not continue. UGA= stop codon.

You'll have to do the mutant
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