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rjandmj82 rjandmj82
wrote...
Posts: 83
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11 years ago
i dont understand this last part of my homework. Can anyone tell me the answer or tell me how to do it? I have the three anticodons for mRNA. Here they are:
#1 AUCCGGUAGCCUUAGUUUAC
#2AUGCCCCCGAUUCUCUUGA
#3AUGGACAAUUCGAUGUUUUAA

any help is much appreciated!
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Replies
wrote...
11 years ago
U is correspondant to A and A is correspondant to U.
G is correspondant to C and C is correspondant to G.

You are looking for the opposite nucleotide (A/U/C/G) for each of the three problems.
So, first one: UAGGCCAUCGGAAUCAAAUG

Try the other two on your own Slight Smile
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julie7julie7
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11 years ago
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wrote...
11 years ago
These are the codons of mRNA and you have to find the amino acids coded by them. This will help you.

http://www.biologycorner.com/resources/codon.gif

http://waynesword.palomar.edu/images/codon1.gif
wrote...
11 years ago
Go to the codon chart here:          http://en.wikipedia.org/wiki/Genetic_code#RNA_codon_table

Codons are read in 3's, so  for #1: AUC, CGG, UAG, CCU, UAG, UUU, AC

AUC is isoleucine
CGG is arginine
UAG is actually a STOP codon, so this terminates the sequence
so #1 is isoleucine-arginine

#2 AUG is methionine, which is the important start codon, necessary for most protein synthesis to begin, so #1 above probably wouldnt make any protein, as it has no start codon, even though it does technically code for amino acids.

so just continue #2, next is CCC = proline,  CCG = proline, AUU isoleucine, all the way down. Usually you need sets of 3's, and in #1 you end with AC and #2 just has A, so idk what to tell you about that part
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