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microB microB
wrote...
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12 years ago
If you cross two plants heterozygous for five different traits (AaBbCcDdEe), what is the probability that the offspring will exhibit the phenotype A, b, c, D, e?
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wrote...
12 years ago
Do each one separately -eg.

Aa x Aa gives 3 showing A and one showing a (AA, Aa, Aa, aa).
Bb x Bb - again 3 B to one b
etc

So,offspring exhibiting the phenotype A, b, c, D, e = 3/4 x 1/4 x 1/4 x 3/4 x 1/4 = 9/1024
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