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Home Q & A Board Science-Related Homework Help Mathematics
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nwood313 nwood313
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Posts: 20
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11 years ago
How would you solve for a and b using substitution or elimination?

17e^-1 = e^-1(a - b + 6)
0 = e^-1(-2a + b) + e^-1(a - b + 6)

Detailed steps would be much appreciated, thank you!
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wrote...
#1
11 years ago
First, multiply both sides of each equation by e to get rid of e^-1. You get 17=a-b+6 and
-2a+b+a-b+6=0. You can simplify the second equation to -a+6=0. Subtract 6 from both sides. -a=-6. a=6. Substitute a=6 into the first equation and you get 6-b+6=17. Simplify. 12-b=17. Subtract 12 from both sides. -b=5. Divide by -1. b=-5. So, the solution is a=6 and b=-5.
Answer accepted by topic starter
fireflowerfireflower
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#2
Posts: 34
Rep: 0 0
11 years ago
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