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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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gh1991 gh1991
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13 years ago
the reaction is first order in cycloprpane and has a measured rate constant of 3.36 *10^-5 s^-1 at 720 K. if the initial cyclopropane concentration is .0445 M, what will the cyclopropane concentration be after 235 minutes?
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wrote...
#1
13 years ago
ln([A]) = ln([A]0) - k t

you have k value 3.36 *10^-5 s^-1
A0 = 0.0445M
t= 235 minutes convert to seconds (235*60)
temp = 720 k

just substitute all these values in the above equation..make sure you use natural logarithm..
wrote...
#2
13 years ago
oh yeah t is time in seconds not the temperature...
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duddyduddy
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#3
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13 years ago
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gh1991 Author
wrote...
#4
13 years ago
but where does the temperature get plugged into?
wrote...
#5
13 years ago
Kind of like this:

k= 3.36*10^-5
t = 14100 sec.
C3H6 initial= 0.0445M

ln [C3H6]t = (-3.36*10^-5)(14100) + ln [.0445]
wrote...
#6
13 years ago
temperature is constant.. you don't have to use it in your problem.. kind of like outlier..
wrote...
#7
13 years ago
Quote from: bio_kite (13 years ago)
temperature is constant.. you don't have to use it in your problem.. kind of like outlier..

thx for clarifying that
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