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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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juliemandell juliemandell
wrote...
11 years ago
not given the ka and that's what I can't seem to solve for. The exact problem is solve for the ph of a solution of 1 molar HNO2 and 1 molar NaNO2.
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wrote...
#1
11 years ago
As you have said it is necessary to have the Ka or pKa of the HNO2. In any reasonable exam this must either be provided, or you must have access to a list of such values. It is impossible to the problem without this info. I checked my list and I get:
HNO2: Ka = 4.0 x 10-4 pKa = 3.4
Now you should have no problem to apply the H-H equation
pH = pKa + log ([A-]/[HA])
pH = 3.40 + log 1/1
pH = 3.40 + log 1
pH = 3.40

Remember- if [A-] = [HA] the pH = pKa - this is the case here.
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