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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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smith332306 smith332306
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11 years ago
A buffer solution of ascorbic acid and its conjugate base is prepared such that the concentration of the acid is exactly one fourth of its conjugate base.
a) What is the pH of this buffer solution? The Ka of ascorbic acid is 8.0 x 10 ?5.
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#1
11 years ago
Using the Henderson-Hasselbalch equation:
pH = pKa + log [base]/[acid]
pH = - log (8.0 x 10^-5) + log (4/1)
pH = 4.10 + 0.60 = 4.70
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