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clueless clueless
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10 years ago Edited: 10 years ago, clueless
Lets say each concentration was reacted for 5 mins, using varying 3mL solutions in cuvettes. They were then measured in a spectrophotometer to get the following absorbance data.
0.20mM -> 0.592
0.40mM -> 0.942
0.75mM -> 1.598
1.00mM -> 2.307
1.50mM -> 2.498
 How do i convert them to velocity?
I know i have to use beers law and the extinction coefficient(18,300/M*cm)
But im kinda confused here =/

EDIT: I'm going to take a guess that C=A/3l and then Vo=C/(delta)T which in this case, (delta)T would be equal to 5. Using this info, the absorbance reading, 0.592 measures out to 0.005202mM/min.
Are my equations correct? Do i divide C by (delta)T which is equal to 5?
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wrote...
10 years ago Edited: 10 years ago, Neji513
how would c/t give you velocity? c is the speed of light in m/s and t is time. dividing those two will not give you m/s, but it'll give your answer m/s^2 which is acceleration.. so there is a problem with your equations

just using the equation you're given though.. i'm guessing c is the concentration and not the speed of light.....if c is the concentration, you can calculate the rate of change by calculating C and then taking the change in concentrations and dividing it by your time which is 5 minutes
clueless Author
wrote...
10 years ago
Lol alright yea, beers law is Absorbance(A)=extinction coefficient(3)*concentration(c)*path lenght(l)
wrote...
10 years ago
Lol alright yea, beers law is Absorbance(A)=extinction coefficient(3)*concentration(c)*path lenght(l)

yea, so just calculate the concentration. i'm guessing you're testing how an enzyme affects the rate of reaction am i correct? if so, then take the concentration at the end, and the concentration at the beginning, and divide by your total time which is 5 minutes and that should give you the rate of the enzyme. path length should be the width of the cuvette which i believe your teacher should give to you, but you could also measure it
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