One-thousand individuals were screened for their genotype at the MN blood group

One-thousand individuals were screened for their genotype at the MN blood group locus. The numbers of each genotype were:

MM    MN    NN
298    489    213

Assuming random mating, calculate the gene frequency for the M allele and the expected genotype frequencies. Use a chi-squared test to determine that mating is random.

Post Merge: 10 years ago

DId I do this correctly?

MM (p^2)= 298/1000= 0.298
MN (2pq)= 489/1000= 0.489
NN (q^2)= 213/1000= 0.213\

Allele f:
f of M=p=p^2 + ½(2pq)= 0.298 + ½(0.489)= 0.5425
f of N=q=1-p= 1- 0.543= 0.4575

Expected genotype f:
MM (p^2)= (0.5425)^2= 0.294306
MN (2pq)= 2(0.5425)(0.4575)=0.4963875
NN (q^2)= (0.4575)^2= 0.209306

Expected number of individuals:
MM= 0.294 X1000= 294
MN= 0.496X1000= 496
NN= 0.209X1000= 209

Chi-squared test:
X^2= ∑(O-E)^2/E
X^2= (298-294)^2/294 + (489-496)^2/496+ (213-209)^2/209= .05442 + 0.09879 + 0.07655= .2296
X^2= 0.2296
X^2(calculated) < X^2 (table) [3.841, 1df, 0.05] therefore there is no statistical significance and mating is random.