Suppose the counselor found the sum of squared deviations from the mean...

Suppose the counselor found the sum of squared deviations from the mean of the sample to be 135. Given that he tested 10 people, what would be the estimated population variance?


A)   135/10 = 13.5
B)   135/9 = 15.0
C)   10/135 = .074
D)   9/135 = .067


8.   Presume the counselor wants to examine whether there is a change (either an increase or decrease) in procrastination after attending his workshop. If the counselor tests 10 students using the .05 level of significance, what cutoff t score(s) will he use? (You should be able to figure this out without a table.)
A)   2.62, 0, +2.62
B)   +2.262
C)   2.262, 0
D)   2.262, +2.262


ty