In the table below, predict (yes or no) whether or not the E. coli lac operon

1. catabolic repression will occur . that means when Glucose is present , cyclic AMP (cAMP) will be lowered . cAMP cannt bind to the CAP binding protein.cAMP-CAP cannt bind activator binding site . other wise no lactose is present .so overall lac operon cannt activated. Its a negetive control

2. first glucose will be utilized by catabolic repression . Then lactose will transform the repressor protein`s conformations. Then transformed repressor is removed from the operator binding site . Lac operon get activated.

3.when lactose is present then like #2 lac operon activated . Its a positive control.

@Padre, I am confused. Could you fill in the above table for me too? Where it says lac expression for the three parts?

Also, I do not know what parts answer what questions.. could be be more clear?

Thanks! 

Post Merge: 10 years ago

one is neg? three is pos? can you explain why?