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ang1 ang1
wrote...
Posts: 8
Rep: 0 0
10 years ago
A single-turn plane loop of wire with a cross-sectional area 200 cm2 is perpendicular to a magnetic field that increases uniformly from 0.200 T to 2.800 T in 2.20 seconds. What is the magnitude of the induced current if the resistance of the coil is 8.00 Ω?

0 A
2.95 A
3.18 mA
2.95 mA
3.18 A
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wrote...
Staff Member
Educator
10 years ago
The formula for induced EMF is...

ε = ΔNBA/Δt   and that also equals IR

so...

IR = ΔNBA/Δt

I(8) = (1)(2.8 - 0.2)(.02)/2.2

I = 2.95 X 10-3 A   which is 2.95 mA   (Choice D)
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