4.00 moles of a monatomic ideal gas at a temperature of 340 K are compressed adi

Review this and see if it works for you --

For adiabatic process with ideal gasfor which {CV = (5/2)*R}:

     P*Vg = Constant   .....   where g = {(5/2) + 1}/(5/2) = (7/5)

Thus, from the ideal gas law:

   P*V = n*R*T  

     ---->    {(Pfinal /Pinitial}*{Vfinal /Vinitial} = {Tfinal /Tinitial}

     ---->   {(Vinitial)g/(Vfinal)g}*{Vfinal /Vinitial} = {Tfinal /Tinitial}

     ---->   {(Vinitial)(g-1) /(Vfinal)(g-1)} = {Tfinal/Tinitial}

     ---->   {(Vinitial)/(Vfinal)}(g-1) = {Tfinal /Tinitial}

     ---->   Tfinal = (Tinitial)*{(Vinitial)/(Vfinal)}(g-1)

    ---->    Tfinal = (22.9 +273.0)*{(50.0e-3)/(20.0e-3)}(0.4)

     ---->   Tfinal =   426.9 degK    =   153.9 degC

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