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Dextor Dextor
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Posts: 11
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9 years ago
For the following crosses, determine as accurately as possible the genotypes of each parent, the parent in whom nondisjunction occurs, and whether nondisjunction takes place in the first or second meiotic division. Both colorblindness and hemophilia, a blood-clotting disorder, are X-linked recessive traits. In each case, assume the parents have normal karyotypes. 





A. A man and a woman who each have wild-type phenotypes have a son with Klinefelter syndrome (XXY) who has hemophilia.




B.  A man who is color blind and a woman who is wild type have a son with Jacob syndrome (XYY) who has hemophilia.




C.  A color-blind man and a woman who is wild type have a daughter with Turner syndrome (XO) who has normal color vision and blood clotting.







D.  A man who is color blind and has hemophilia and a woman who is wild type have a daughter with triple X syndrome (XXX) who has hemophilia and normal color vision.

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Answer rejected by topic starter
wrote...
Educator
9 years ago
Parents: XXh mother, XY father

Non-disjunction happened in the mother, therefore he inherited the Xh from the mother.
Dextor Author
wrote...
9 years ago
Parents: XXh mother, XY father

Non-disjunction happened in the mother, therefore he inherited the Xh from the mother.

Is that for part D?
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