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fosmanali01 fosmanali01
wrote...
Posts: 78
11 years ago
A sinusoidal function, y = a sinb(x - c) + d has a maximum point at ( pi/4 , 3 ) and a minimum point at ( -pi/4 , -1 ). The values of a, b, c,  and d are

I know what the values of a and d are:

a = 2
d = 1

What are the values of b and c?

Thanks for helping.
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wrote...
10 years ago
The period is pi if you take the difference between the max and min and multiple that by 2. Thus b is 0.5.

c is 0 since the max and min and equal distance apart.
wrote...
10 years ago Edited: 10 years ago, metal_zelda
The period is pi if you take the difference between the max and min and multiple that by 2. Thus b is 0.5.

c is 0 since the max and min and equal distance apart.

I tried plugging pi/4 into your equation and I did not get the same maximum as in the opening post. I believe that b is actually omega (angular speed) rather than the period. If we solve it in this manner, b=2 (when b=2, the period is pi).

I also believe that c is the phase shift rather than the distance of the maximum and minimum. Solving the equation 3=2sin(2(π4c))+1 suggests that c=πk, where kz

I plotted y=2sin(2(x-pi))+1 in mathematica and it seemed to fulfill the requirements of the initial problem (e.g. period of pi, maxima in proper places, etc.), but I'd like someone else to confirm it.
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