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mikael mikael
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10 years ago
A proton with a speed of  5.0 × 105 m/s falls through a potential difference V and thereby increases its speed to  8.0 × 105 m/s. Through what potential difference did the proton fall? 
A) 2000 V 
B) 1300 V 
C) 3300 V 
D) 4600 V 
E) 660 V 
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padrepadre
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9 years ago
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mikael Author
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9 years ago
Thanks again.
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