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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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tink571937 tink571937
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12 years ago
Suppose you ran this same reaction (using the balloon setup as seen in the video) on your own with two different flasks. In Flask A, you reacted 1.65 g Mg with 0.136 mol HCl. In Flask B, you reacted 2.21 g Mg with 0.098 mol HCl. Which ballon will inflate the most? Explain (in detail) why.

Why did these balloons inflate? Write and discuss a balanced chemical equation for this reaction and use it to help explain your answer.

The video comes from Thinkwell if that helps.
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#1
12 years ago
The ratio is 2:1 HCl over Mg. So I converted the Mg from grams to moles and got Flask A .067 mole Mg and .136 mole HCl. Which is a 2:1 ratio. Flask B got .090 and .098 about a 1:1 ratio. Flask A would produce .067 mole of Hydrogen gas. Flask B would only being able to produce .049.
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#2
12 years ago
Flask A will produce more Hydrogen, since in flask B the HCl is the limiting reagent (stoichiometrically).
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