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Home Q & A Board Science-Related Homework Help Physics
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aaablls aaablls
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9 years ago
Light of wavelength 630 nm passes through a grating and then onto a screen located several meters from the grating. The 1st order bright band is located 0.29m from the central maximum. Light from a second source produces a band 0.23m from the central maximum.
Determine wavelength of second source
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#1
Educator
9 years ago
bio_man: Please so a better job with the topic title.
The formula that governs this is y/L = m(wavelength)/d

Since L and d are constant, we can set up a ratio

m(wavelength)/y = m(wavelength)/y

1(630)/.23 = 1(wavelength)/.2

wavelength ~= 484.6 nm
aaablls Author
wrote...
#2
9 years ago
thank you!!
wrote...
#3
Educator
9 years ago
Make sure the calculations are correct though Slight Smile
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