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sharon1234 sharon1234
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Posts: 686
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6 years ago
In a 100 bp stretch of a gene, a researcher counts 25 nonsynonymous substitutions, 30 synonymous substitu-tions, and 65 nonsynonymous sites. What type of selection is operating on this gene sequence? Show your work.
 
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wrote...
6 years ago
ANS:
Ka = 25/65 = 0.385, Ks = 30/35 = 0.857, Ka/Ks = 0.449, which indicates purifying selection.
sharon1234 Author
wrote...
6 years ago
Passed my quiz!!!
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