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9 years ago
If the initial pressure of a system was 1.00 atm and the volume was halved and the temperature was tripled, what is the final pressure?
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9 years ago
I'm assuming the system is in gaseous state. If so, you can use the formula PV=nRT to calculate the change in pressure.
The number of moles of gas remained the same, so n and R are constant.
So the new equation would be P(1/2)V=nR(3)T
To make the equation balance out, pressure needs to be 6 times the original, so the coefficient on both sides would be 3.
Thus, the final pressure would be 6 atm
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