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Aliya1 Aliya1
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Posts: 351
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5 years ago
In mice, black fur (B) is dominant over brown fur (b). Two black mice had brown offspring. Which of the following offspring genotypes could result from the parental cross? Select one: a. BB, Bb, and bb,b. Bb and bb,c. BB and Bb,d. bb.
#2. In mice, black fur (B) is dominant over white fur (b).A testcross was performed with a black mouse.  Which of the following conclusions about the genotypes of the parental mice is the ONLY possibility for the given outcomes?Select one:
a. If any of the offspring have white fur, the parental black mouse genotype is heterozygous.
b. If all the offspring have white fur, the parental black mouse genotype is homozygous.
c. If all of the offspring have black fur, the parental black mouse genotype is homozygous.
d. If all of the offspring have black fur, the parental white mouse genotype is heterozygous.
#3.There is a lack of dominance in four o’clock plant flowers. When a red flower is crossed with a white flower, a pink flower is produced. In an experiment, pink flowers were self-pollinated. The phenotype ratio of the F2 generation is Number:
                                                                      Flower colour: red,white,pink
#4.Phenylthiocarbamide (PTC) is an organic compound that either tastes extremely bitter or is tasteless, depending on the genotype of the taster. The tasting allele is dominant over the non-tasting allele.

Normal skin pigmentation is dominant over albinism. (It is important to note that this example of PTC tasting cannot be explained with simple genetics, but for the purpose of this question, assume that it can.)

A normally-pigmented woman who cannot taste PTC has an albino father who can taste PTC. The woman married an albino man who can taste PTC and whose mother cannot taste PTC.
For the married couple,

1. correctly identify their genotypes, (1 mark)
2. complete a Punnett square showing the expected offspring of the couple, and (1 mark)
3.identify the genotypic and phenotypic ratios of their offspring (1 mark)
#5.On pea plants, the location of flower growth is an inheritable trait. Axial flower position is dominant over the recessive trait of terminal flower position.

In the parental generation, a homozygous dominant axial flower position pea plant is crossed with a terminal flower position pea plant.

1.Draw a Punnett square of the F1 gametes producing the F2 offspring. (1 mark)
2.In the F2 generation, what is the probability one plant will have a terminal flower position? (1 mark)
3.In the F2 generation, what is the probability two plants will have axial flower positions? Show all work. (1 mark)
Hi There, I am new here and i need help with these 5 questions. Sorry for this post being fairly long.
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Replies
wrote...
5 years ago
In mice, black fur (B) is dominant over brown fur (b). Two black mice had brown offspring. Which of the following offspring genotypes could result from the parental cross? Select one: a. BB, Bb, and bb,b. Bb and bb,c. BB and Bb,d. bb.

If that's the case, the two black mice were likely heterozygous (Bb).

   B   b
B   Bb   Bb
b   Bb   Bb

Answer accepted by topic starter
terriroberts96terriroberts96
wrote...
Posts: 124
5 years ago
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This verified answer contains over 130 words.
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wrote...
5 years ago
#3.There is a lack of dominance in four o’clock plant flowers. When a red flower is crossed with a white flower, a pink flower is produced. In an experiment, pink flowers were self-pollinated. The phenotype ratio of the F2 generation is Number:
                                                                      Flower colour: red,white,pink

This phenomenon is called incomplete dominance. Let's say the pink flowers are Rr.

   R   r
R   RR   Rr
r   Rr   rr

1 red
2 pink
1 white


What's highlighted is the answer.

wrote...
Educator
5 years ago
#4.Phenylthiocarbamide (PTC) is an organic compound that either tastes extremely bitter or is tasteless, depending on the genotype of the taster. The tasting allele is dominant over the non-tasting allele.

Normal skin pigmentation is dominant over albinism. (It is important to note that this example of PTC tasting cannot be explained with simple genetics, but for the purpose of this question, assume that it can.)

A normally-pigmented woman who cannot taste PTC has an albino father who can taste PTC. The woman married an albino man who can taste PTC and whose mother cannot taste PTC.
For the married couple,

1. correctly identify their genotypes, (1 mark)
2. complete a Punnett square showing the expected offspring of the couple, and (1 mark)
3.identify the genotypic and phenotypic ratios of their offspring (1 mark)

This one is hard.

p represents the letter for PTC
a represents the letter for albinism, therefore capital A means you DON'T have it

Let's start with #1

The woman's genotype is: ppAa
The man's genotype is: Ppaa

Now, for #2 and #3

See the attachment!
Post Merge: 5 years ago

#5.On pea plants, the location of flower growth is an inheritable trait. Axial flower position is dominant over the recessive trait of terminal flower position.

In the parental generation, a homozygous dominant axial flower position pea plant is crossed with a terminal flower position pea plant.

1.Draw a Punnett square of the F1 gametes producing the F2 offspring. (1 mark)
2.In the F2 generation, what is the probability one plant will have a terminal flower position? (1 mark)
3.In the F2 generation, what is the probability two plants will have axial flower positions? Show all work. (1 mark)

Let's use the letter, R for dominant Axial. Therefore, RR and Rr gives dominant. rr represents terminal.

   R   R
r   Rr   Rr
r   Rr   Rr

Rr is the F1 gametes

   R   r
R   RR   Rr
r   Rr   rr

F2 offspring is RR, Rr*2, and rr.

#2, 25%, 1 in 4.

#3, 75%, 3 in 4 will have this configuration
 Attached file 
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Aliya1 Author
wrote...
5 years ago
Thank you guys so much Slight Smile
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