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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Vbustos83 Vbustos83
wrote...
6 years ago
At a given temperature, K = 46.0 for the reaction
4 HCl (g) + O2 (g)   2 H2O (g) + 2 Cl2 (g)
At equilibrium, [HCl] = 0.150, [O2] = 0.395, and [H2O] = 0.625. What is the concentration of [Cl2] at equilibrium?
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wrote...
#1
Educator
6 years ago
\(k=\frac{\left[H_2O\right]^2\left[Cl_2\right]^2}{\left[HCl\right]^4\left[O_2\right]}\)

\(46.0=\frac{0.625^2\left[Cl_2\right]^2}{0.150^4\cdot 0.395}\)

\(46.0\times 0.150^4\cdot 0.395=0.625^2\left[Cl_2\right]^2\)

\(\frac{46.0\times 0.150^4\cdot 0.395}{0.625^2}=\left[Cl_2\right]^2\)

Square-root both sides to eliminate the ²

\(\sqrt{\frac{46.0\times 0.150^4\cdot 0.395}{0.625^2}}=Cl_2\)

\(0.15345=Cl_2\)

To 3 significant figures, it's 0.153 M Slight Smile
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