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Lola617 Lola617
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5 years ago
Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane?

• The positions of the Cl atoms induce the net formation of the terminal alkyne.

• The strong base deprotonates the terminal alkyne and removes it from the equilibrium.

• The terminal alkyne is not favored in this reaction.

• The terminal alkyne is more stable than the internal alkyne and is naturally the favored product.

• The resonance favors the formation of the terminal rather than internal alkyne.
Textbook 
Organic Chemistry

Organic Chemistry


Edition: 9th
Authors:
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tiffanyswhtiffanyswh
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5 years ago
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Lola617 Author
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5 years ago
Smart ... Thanks!
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