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2 weeks ago
The pH of a 0.401 mol/L solution of sulfurous acid is 1.16 (used as an example, your value may be different). Based on this evidence, the Ka for sulfurous acid is?

Would we just look at our chart on pages 8 and 9 and say 0.014?
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2 weeks ago
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Solution attached.

If you want to learn how this is done on your own, I suggest you watch this excellent tutorial:



Bye for now Slight Smile
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wrote...
2 weeks ago
Just to confirm where did you get 0.06918= [H3O+]?
wrote...
Educator
2 weeks ago
They're asking for Ka though (answer is highlighted). You're giving the concentration, watch out for that. But to answer your question, as per the attachment, it's identical to what I found too for the hydronium concentration.
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