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wrote...
Posts: 242
2 weeks ago
Pew Research reports that 63% of the U.S. adult cell phone owners use their phone to go online. A company wants to target 16- to 24-year olds for advertising and they wonder if that age group has a similar pattern of phone use.

The company wants to estimate the true percentage of 16- to 24-year old cell phone owners who use their phone to go online to within ±7.5%, with 95% confidence. How many cell phone owners in this age group should they sample?
Textbook 

Stats: Modeling the World


Edition: 4th
Authors:
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Answer verified by a subject expert
wrote...
Posts: 238
2 weeks ago
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ME = z*
0.075 = 1.96
=
n = 159.196 ≈ 160
They should sample at least 160 applicants.
1

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wrote...
2 weeks ago
Pew Research reports that 63% of the U.S. adult cell phone owners use their phone to go online. A company wants to target 16- to 24-year olds for advertising and they wonder if that age group has a similar pattern of phone use.

They ignore your advice in Question 1 and just select a random sample of 300 cell phone users aged 16 to 24, and find that 206 of those surveyed use their phone to go online. Create the confidence interval.
wrote...
2 weeks ago
We have a random sample of less than 10% of the number of cell phone users in this age group, with 206 successes and 944 failures, both of which are at least ten, so a Normal model applies. The confidence interval is (0.634, 0.739).
wrote...
2 weeks ago
Thanks for your help!
wrote...
2 weeks ago
Pew Research reports that 63% of the U.S. adult cell phone owners use their phone to go online. A company wants to target 16- to 24-year olds for advertising and they wonder if that age group has a similar pattern of phone use.

Should the company conclude that the percentage of cell phone owners in this age group who use their phone to go online is different from 63%? Explain.
wrote...
2 weeks ago
Yes. Since 63% does not lie in the confidence interval it's unlikely that the percentage of all cell phone owners aged 16 to 24 who use their phone to get online is 63%.
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