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michlee michlee
wrote...
Posts: 461
4 years ago
For the given data set, find the a. mean b. median c. mode (or state that there is no mode) d. midrange.

A company advertised that, on the average, 96% of their customers reported "very  high satisfaction" with their services.  The actual percentages reported in 15 samples were the following:
96, 96, 92, 35, 74, 96, 92, 74, 96, 96, 35, 92, 92, 96, 35
a. Find the mean, median, mode and midrange. b. Which measure of central tendency was given in the advertisement? c. Which measure of central tendency is the best indicator of the "average" in this situation?

▸ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. median
c. mean

▸ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. mode

▸ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. median

▸ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. mean
Textbook 
Thinking Mathematically

Thinking Mathematically


Edition: 6th
Author:
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bli14bli14
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Posts: 390
4 years ago
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michlee Author
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4 years ago
Thank you, thank you, thank you!
wrote...

Yesterday
This helped my grade so much Perfect
wrote...

2 hours ago
Thanks for your help!!
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