Need help braking down linkage mapping and recombination

1) https://imgur.com/zy4kV0n

Particularly about question 2, is Tt a gene and Dd a gene for warty,dull fruit? So we got two genes on each chromosome right? And for smooth, glossy we get tt and dd. Is their a simple way to approach this question? What we did in class is that we arrived with TD/td td/td and TD/td once more to be 92% nonrecombinent and that to get a warty, glossy fruit we are looking for a tD which is not found in nonrecombinents but only in recombinents and since recombinents are 50% between the two gametes that means 8%/2 = 4% * 300 = around 12 tD progeny. Did I do the TD/td td/td and TD/td once more to be 92% nonrecombinent correct? The lecture slide shows this instead: https://imgur.com/pUmS75v I am not sure how the 92% td/td and TD/td are being shown like this.

2) https://imgur.com/Va4cjHZ

When it says "if parents AABBCC and aabbcc mate" then it means we have ABC/ABC parent mates with abc/abc yeah? Or would it be ABC/abc x abc/abc or actually just simply ABC/abc? And why? If its actually just ABC/abc then what about other ABC/abc? Now says it either or, how do I go about finding progeny of offspring? Do I just do cross between AB and then cross between BC and then cross between AC and then no cross and all the 8 possible genotypes is going to be offspring? Or is this wrong? Actually now writing this I think genotype of offspring between AABBCC and aabbcc parent is going to be ABC/abc which is ABC from one parent and abc from another.

3) https://imgur.com/tbsaDg2

For question 4: Whats a 3 gene triple heterozygote? Does that mean ABC/abc is actually AaBbCc which would qualify as triple heterozygote? Then how would I go about to make chromosomes have double and paired, that means now I have 4 chromosomes? So would it look like this? http://Https://imgur.com/5Mz3DSP

For question 5, I now know that we gona have 8 different genotypes but the question is weird, I am not sure whats its asking, but the teacher made it clear that we just do 2 single cross and 1 double cross. But going back to question its like saying ABC/abc x abc/abc ? And if so then how do I end up with parental genotype

4) https://imgur.com/r2pCRgw

For a. When it says imagine 100 AaBbCc are we talking about two chromosomes or actually 4 of them?

For b. Very simple as well just the two haploid gametes that will be most common gona be ABC and abc.

For c, Also simple the double cross over gona be AbC and aBc

For d, also simple only possible gamete from reccessive individual gona be abc.