Top Posters
Since Sunday
e
5
e
4
4
d
4
R
4
o
3
p
3
t
3
3
m
3
p
3
m
3
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
i_love_science i_love_science
wrote...
Go to Answer
Posts: 38
Rep: 1 0
3 years ago
Gases N2(g) and H2(g) are added to a previously evacuated container and react at a constant temperature according to the following chemical equation:
N2(g) + 3H2(g)→2NH3(g)
If the initial pressure of N2(g) was 1.2atm, and that of H2(g) was 3.8atm, what is the partial
pressure of NH3(g) when the partial pressure of N2(g) has decreased to 0.9atm.

(A) 0.30atm
(B) 0.60atm
(C) 0.9atm
(D) 1.8atm (E) 3.8atm

The solution given was (B) 0.60 atm. It stated that because of the stoichiometric ratio of 1:2 for N2(g):2NH3(g), when the pressure of N2(g) decreases by 0.30 atm, then the pressure of 2NH3(g) increases by 2 x 0.30 = 0.60 atm, which will be its partial pressure.

I don't understand why this is the case.

Thanks.
Read 70 times
1 Reply
Replies
Answer accepted by topic starter
Tgrabez7Tgrabez7
wrote...
#1
Posts: 93
Rep: 1 0
3 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  924 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 65
  
 464
  
 123
Your Opinion
How often do you eat-out per week?
Votes: 80
Previous poll results: Should Ph.D.'s be addressed as doctors?