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Determine exact value of tan2x,sin2x, and cos2x

marinejas

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4 years ago

Determine exact value of tan2x,sin2x, and cos2x

if cscx= -17/15 and pi<x<3pi/2

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bio_man

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#1

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marinejas Author

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#2

4 years ago

Thanks bio_man, but why is 8 negative (triangle)?

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bio_man

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#3

Educator

4 years ago

Imagine plotting a point in the third quadrant, both of the coordinates would be negative.

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marinejas Author

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#4

4 years ago

oh yes sorry I knew that, just confused myself

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bio_man

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#5

Educator

4 years ago

Feel free to mark this thread solved once you're done

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marinejas Author

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#6

4 years ago

Just a little confused with sin and cos, I got 0.0654031 for sin but I have a feeling its wrong, the answer wasn't given for this question.

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bio_man

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#7

Educator

4 years ago

For sin2x, the answer should be exactly:

$\frac{240}{289}$

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marinejas Author

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#8

4 years ago

would you mind showing me how you got that as well as for cos? If that's okay, just want see where I went wrong. Thanks.

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bio_man

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#9

Educator

4 years ago

Sure, for cos2x, find the answer to this:

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marinejas Author

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#10

4 years ago

The answer for cos is 64/289, but can you show the steps on you put it in that format 1-2 (-15/17)? Also you didn't use -15/-8?

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