How to factor completely

theepicseal

wrote...

Posts: 50

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3 years ago

Hi! May someone please assist me with answering these questions?

Factor completely :
1) x^2-2+1
2) 8x^2+24xy+18^2
3) 3x^4-24x^2+48
4) 4r^2(w+2) -25(w+2)

Thanks so much!!! Smiling Face with Open Mouth

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bio_man

wrote...

Educator

3 years ago

Trial and error: -- QUESTION 1

Factoring a Quadratic with Two Variables -- QUESTION 2

Disguised Quadratics -- QUESTION 3

Factorings a difference of squares: -- QUESTION 4

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theepicseal Author

wrote...

3 years ago

Thanks! For question 2, when you plugged the 12’s back into the original expression, you dropped the y, as it was shown as xy in the original expression. Was that a mistake? I thought it had to still be 12xy + 12xy

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bio_man

wrote...

Educator

3 years ago

Oh dear... my mistake. Did you watch the second video? It's like the exact same question, check it out

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theepicseal Author

wrote...

3 years ago

I’ll check it out now! So now that I know it’s supposed to be 12xy, does factoring out 4x still work for that? Cause it confuses me how to factor 4x from 12xy. Is it possible to factor something out that has a variable (x or y for ex) that one of the coefficients in the expression don’t have? Or must factors contain something that every single coefficient also contains? We can’t just skip over that term can we?

Post Merge: 3 years ago

*when we are factoring something out

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bio_man

wrote...

Educator

3 years ago

I think the only difference will be the 6 and 3 will be 6y and 3y instead

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theepicseal Author

wrote...

3 years ago

Ok I’ll try it again!

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