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When one mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 353.0 K, 30.40 kJ of energy (heat) is absorbed and the volume change is +28.90 L. What is ΔE for this process? (1 L·atm = 101.3 J)


30.40 kJ

59.30 kJ

33.33 kJ

1.50 kJ

27.47 kJ
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Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach


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