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graceeylee graceeylee
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For a solution equimolar in HCN and NaCN, which statement is false?


▸ This is an example of the common ion effect.

▸ The [H+] is larger than it would be if only the HCN was in solution.

▸ The [H+] is equal to the Ka.

▸ Addition of more NaCN will shift the acid dissociation equilibrium of HCN to the left.

▸ Addition of NaOH will increase [CN–] and decrease [HCN].
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Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach


Edition: 3rd
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HasnaHasna
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Thank you, thank you, thank you!
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