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heberleber heberleber
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Given the following thermochemical equations:
(kJ/mol)
4 FeS2(s) + 11 O2(g)  → 2 Fe2O3(s) + 8 SO2(g) ΔrH° = -3307.9
2 H2S(g) + 3 O2(g)  → 2 H2O(l) + 2 SO2(g) - 1125.2
4 FeO(s) + O2(g)  → 2 Fe2O3(s) - 578.2
2 Fe(s) + O2(g)  → 2 FeO(s) - 544
H2(g) + S(s)  → H2S(g) - 20.2
2 H2(g) + O2(g)  → 2 H2O(l) - 571.7

Compute the ΔfH° for FeS2(s) in kJ/mol.

▸ -1233.9 kJ/mol

▸ -2893.9 kJ/mol

▸ -24.3 kJ/mol

▸ -183.5 kJ/mol

▸ -70.0 kJ/mol
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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