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pjstaud pjstaud
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1 months ago

Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride?

Ti(s) + 2 Cl2(g) → TiCl4(l)

ΔH = 804.2 kJ/mol

TiCl4(g) → 2 Cl2(g) + Ti(s)

ΔH = 763.2 kJ/mol



▸ +41.0 kJ/mol

▸ –1567.4 kJ/mol

▸ 1567 kJ/mol

▸ –41.0 kJ/mol

▸ –763.7 kJ/mol
Textbook 
Chemistry: Atoms First

Chemistry: Atoms First


Edition: 4th
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chelzchelz
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