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jdwalker9 jdwalker9
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2 years ago
The solubility product constant of PbI2(s) is 7.1 × 10-9. How many moles of PbI2 will precipitate if 250 mL of a 0.200 M solution of NaI(aq) are added to 150 mL of 0.100 M solution of Pb(NO3)2(aq)? You may neglect hydrolysis.

▸ 0.050 mol

▸ 1.3 × 10-5 mol

▸ 0.015 mol

▸ 5.6 × 10-3 mol

▸ 0.040 mol
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
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MayhemMayhem
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Thank you, thank you, thank you!
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