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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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louist louist
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2 years ago
Consider the following sets of quantum numbers:
1. n= 3, l= 0, m= 3
2. n = 4,l = 4, m = 4
3. n= 6,l=3, mp=-3
4. n= 20,l= 19, m = 18
5. n=-2,l=-1, m=-1
Which of the above combinations represent a set of allowed quantum numbers?
a) 3,4
b)1,
 c)2, 3, 5
d)1,2,5
e)2,3,4
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#1
Educator
2 years ago Edited: 2 years ago, bio_man
Impossible:

2. n = 4,l = 4, m = 4
L is always 1 less than n, so the maximum L can be is 3
5. n=-2,l=-1, m=-1
Can't have negative n
1. n= 3, l= 0, m= 3
If L is 0, the m should be 1 (m=2(L)+1)

I think the only correct answer is \(\boxed{a) 3,4.}\)

Please watch this video:



and this one:
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