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megan.xo megan.xo
wrote...
Posts: 127
3 months ago
If in an △ABC, 2cosA·sinC = sinB, then the triangle is?
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wrote...
3 months ago
2cosA.sinC=sin(C+A)
=sinC.cosA+cosC.sinA
⇒cosAsinC−sinAcosC=0
⇒sin(C−A)=0
⇒C=A
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