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Annonn Annonn
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Posts: 213
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2 years ago
 Consider the following electrochemical reaction:
Cu2+(aq) + Zn(s) →  Zn2+(aq) + Cu(s)   E° = +1.10 V
What will be the cell potential for this reaction when [Cu2+] = 1.00 M and [Zn2+] = 1.0 x 10-3 M?

+1.14 V

+1.19 V

+1.01 V

+1.06 V

-1.90 V
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wrote...
#1
Valued Member
2 years ago
ecell = 1.10 - (0.0592/2) log (1.00 M / 1.0 x 10-3 M)
Annonn Author
wrote...
#2
2 years ago
I'm a little confused about what that means because I'm given a list of options to choose from and that isn't on the option list
wrote...
#3
Valued Member
2 years ago
Use your calculator, should be 1.01
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