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RioNii RioNii
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3 years ago
Given the following two reactions:

(1)Pb(s) + Cl2(g)PbCl2(s)       H(1) = -359.4 kJ

(2)Hg(l) + Cl2(g)HgCl2(s)       H(2) = -224.3 kJ

Calculate the enthalpy change for the following reaction:

(3) Pb(s) + HgCl2(s) PbCl2(s) + Hg(l)     
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bio_manbio_man
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3 years ago
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RioNii Author
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3 years ago
Thank you sir!
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Educator
3 years ago
No problem. I have marked it solved Slight Smile
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