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Home Q & A Board Laboratory Help Introductory Courses
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O.G. Mann O.G. Mann
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A year ago
For Vf=500 and DF=100, Vi=5 and Vf=500 and DF=125, Vi=4, 9uL of the 700uL 1:75 solution would be required for the two 500uL solutions. The initial solution concentration would be 100% for the two additional dilutions. They are not serial. Am I missing something?
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wrote...
#1
Educator
A year ago
I'll try to sort this out for you.

500uL at 1:100 means that you start with a volume of 5 μL at 100% concentrations, which you add 495 μL of solvent to make 500 μL in total.

Df = Vf / Vi
Df = 500 μL / 5 μL
Df = 100

Thus, 1:100 dilution.

Using C1V1 = C2V2, since the initial 5 μL at 100% concentration, then:

(1)*(5μL) = C2*(500μL)
5μL/500μL = C2 = 0.01

Thus, the new concentration is 0.01
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