Compartment model

Hello,

\(C_p=19e-4.8t+13e-0.15t\)

\(k_{21}=2.04\ hr^{-1}\)

Is this what the equations look like?

yes

I don't think so. Are you sure it is not:

\(C_p=19e^{-4.8t}+13e^{-0.15t}\)

??

The hybrid distribution half-life is a parameter that describes the distribution of a drug between the central and peripheral compartments in a two-compartment model. It is calculated as the ln(2) divided by the sum of the elimination rate constant (k10) and the distribution rate constant (k12).

In this case, the elimination rate constant (k10) is not given, but we can use the given information to calculate k10. From the equation Cp = 19 e^(-4.8t) + 13 e^(-0.15t), we can see that the initial concentration (at t=0) is Cp(0) = 19 + 13 = 32 mg/L. At steady state, the infusion rate (R) equals the elimination rate (k10Cp), so we can set R = k10Cpss, where Cpss is the steady-state concentration. Solving for k10, we get:

k10 = R/Cpss = (10 mg/kg * 70 kg)/(32 mg/L * 1) = 21.875 hr^-1

Now we can calculate the hybrid distribution half-life:

k12 = 2.04 hr^-1
k10 = 21.875 hr^-1

hybrid distribution half-life = ln(2) / (k10 + k12)
= ln(2) / (21.875 + 2.04) hr^-1
= 0.030 hr or 1.8 minutes

Therefore, the hybrid distribution half-life of azatamycin in human subjects after a single IV dose (10 mg/kg) is approximately 1.8 minutes.

yes it's this

Post Merge: 3 months ago

Thank you!