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BurgEltz BurgEltz
wrote...
Posts: 7
Rep: 0 0
9 years ago
Hi

I am doing a chemistry quiz for Uni and am stuck on a question, google has not been my friend.
question is:

An element has 2 isotopes. the natural abundance of the major isotope (6.0176amu) is 88.618%. the other isotope has a 7.0182amu. calculate the weight in amu of the naturally occurring element.

Any help is much appreciated Slight Smile
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Replies
wrote...
9 years ago
You need to find the percentage of the second isotope,  by subtracting the percentage of the given isotope from 100 this gives you 11.382%. You then take 11.382 divide it by hundred and multiply it by 7.0182. Then take 88.618 divide it by 100 and multiply by 6.0176. Then add the two answers and you get 6.132 amu
BurgEltz Author
wrote...
9 years ago
Thanks Slight Smile
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