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shahinakanwal shahinakanwal
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9 years ago
How many C atoms are in 3.50 mol of glucose (C6H12O6)? show work
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wrote...
9 years ago
3.50mol X (6mol C)/(1mol C6H12O6) = 21mol C
21 mol C X (6.02X10^23 atoms)/(1mol)= (6.02X10^23)(21)
=1.26X10^25
easy peasy
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