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Whelan Whelan
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8 years ago
A gaseous reaction occurs by a two-step mechanism, shown below.

   Step 1: AX +Y2 Leftwards Arrow Rightwards Arrow AXY2      fast
   Step 2: AXY2 + AX → 2 AXY      slow

Including concentration of only reactants and products, what is the rate law for this reaction?
A) Rate = k[AX][XY2]
B) Rate = k[AXY2]/[AX][Y2]
C) Rate = k[AX]2[Y2]
D) Rate = k[AXY]2/[A Y2][AX]
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Introductory Chemistry Essentials

Introductory Chemistry Essentials


Edition: 5th
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hbutler2hbutler2
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#2
4 years ago
A gaseous reaction occurs by a two-step mechanism, shown below.

    Step 1:   A2 ⇄ 2 A   fast
    Step 2:   A + B → AB     slow

Which is the rate of the reaction?

HELP!!!
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#3
4 years ago
thanks
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