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Whelan Whelan
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The balanced equation for the solubility equilibrium of Ba(OH)2 is shown below. What is the equilibrium constant expression for the Ksp of Ba(OH)2?

Ba(OH)2(s) Leftwards Arrow Rightwards Arrow Ba2+(aq) + 2 OH-(aq)

A) Ksp = {[Ba2+][OH-]2}/{[Ba(OH)2][H2O]}
B) Ksp = {[Ba2+][OH-]2}/[Ba(OH)2]
C) Ksp = [Ba2+][OH-]2
D) Ksp = 1/{[Ba2+][OH-]2}
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Introductory Chemistry Essentials

Introductory Chemistry Essentials


Edition: 5th
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hbutler2hbutler2
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Whelan Author
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9 years ago
Thanks for your help!!
Zacellison
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Yesterday
You make an excellent tutor!
decibul
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2 hours ago
Brilliant ツ
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