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quixie quixie
wrote...
8 years ago
Calculate the slope of the line tangent to \({7x^{2}}+3xy+{6y^{2}}=4\) at (1,-3)

a. slope = \(\frac{23}{33}\)

b. slope = \(\frac{5}{33}\)

c. slope = \(\frac{33}{5}\)

d. slope = \(\frac{2}{9}\)
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