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quixie quixie
wrote...
8 years ago
Find the second derivative, y"(x), of \(-3{sqrt{{x^{3}}}}+2{sqrt{{y^{3}}}}=-2\)

a. y"(x) = \(\frac{3}{4{sqrt{xy}}}-\frac{y'}{2y}\)

b. y"(x) = \(\frac{3}{4{sqrt{xy}}}-\frac{{(y')^{2}}}{2y}\)

c. y"(x) = \(-\frac{3}{2{sqrt{xy}}}-\frac{{(y')^{2}}}{2y}\)

d. y"(x) = \(-\frac{3}{4{sqrt{xy}}}+\frac{{(y')^{2}}}{2y}\)
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