× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Mathematics
New Topic  
quixie quixie
wrote...
8 years ago
Compute the sum and the limit of the sum as n -> infinity.

\({\sum_{n=1}^n \frac{1}{n}[13(i/n)^2-9(i/n)]}\)

a. Sum = \(\frac{13(n+1)(2n+1)}{6n^2}-\frac{9(n+1)}{2n}\) ; limit of sum as n -> infinity is -1/6

b. Sum = \(\frac{(n+1)(2n+1)}{13n^2}-\frac{n+1}{9n}\) ; limit of sum as n -> infinity is -17/117

c. Sum = \(\frac{13(n+1)(2n+1)}{6n^2}-\frac{9(n+1)}{2n}\) ; limit of sum as n -> infinity is 0

d. Sum = \(\frac{(n+1)(2n+1)}{13n^2}-\frac{n+1}{9n}\) ; limit of sum as n -> infinity is 17/117
Read 455 times

Related Topics

New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  948 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 248
  
 279
  
 322
Your Opinion
Which of the following is the best resource to supplement your studies:
Votes: 292
Previous poll results: What percentage of nature vs. nurture dictates human intelligence?